What is the buoyancy-related weight of water displaced by a dive bell in pounds at the common displacement of 193 ft3?

To determine the buoyancy-related weight of water displaced by a dive bell at a displacement of 193 cubic feet, we need to understand Archimedes' principle, which states that an object submerged in fluid will displace a volume of fluid equal to its own volume. The weight of this displaced water is what contributes to the buoyancy force acting on the dive bell.

To convert cubic feet of water into pounds, we use the weight of water, which is approximately 62.4 pounds per cubic foot at standard temperature and pressure. Therefore, to compute the weight of the displaced water, the calculation would be:

Weight = Volume × Density of Water

Weight = 193 ft³ × 62.4 lbs/ft³

Carrying out this multiplication gives:

Weight = 193 × 62.4 ≈ 12047.2 pounds.

Upon checking the choices, we match this calculated weight to the common displacement values. While 1952 lbs appears correct at first glance as an alternative answer, it doesn't correspond to the actual conversion of the displacement volume into weight.

The correct answer aligns closer to the most common buoyancy-related consideration in diving operations, affirming that the choice indicating 1952 lbs, while seemingly plausible, would